Football WOD – Jan 24, 2016

ICA will be open today for the 10:00 am only!  Please remove your name from the sign up if you are not going to attend.  A snow emergency is still in effect for Phoenixville which comes with a hefty fine if you get stuck.  Be careful out there.

“Fight Gone Worse”

Complete 3 rounds of 1 minute of work at each station:

  • DB thrusters (50/30#)
  • Power snatch (95/65#)
  • Box jumps (20/16″)
  • Push presses (95/65#)
  • Row (1 cal = 1 rep)

Rest 1 minute after each 5 minute round.

Weather Notes:  Stay tuned tomorrow morning to see if classes are still on.  The gym can physically be opened but we don’t want to endanger ICAers or hinder the progress of the street crews by opening irresponsibly.  We’ll see conditions around 7:00 tomorrow and make a decision.

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This Post Has 0 Comments

  1. Kehl

    If class is on, I hope Murray doesn’t show up. I really don’t want to do his birthday burpees.

    1. ICA admin

      Sounds like a good at-home snow wod to me!

  2. Jimbo

    Well Kehl, you won’t have to worry about burpees because his real birthday was on Thursday!! Thank god!!

  3. Murray

    And my neighborhood still hasn’t been plowed. I am not dedicated enough to snow shoe to ica.

  4. ICA admin

    Hey All,

    I just took a drive to check roads. They’re not good. Parts of 23 have 6 to 8” of snow still. If you don’t have 4 wheel drive, I would not recommend coming in. Also remember that weight of vehicle and number of wheels with power do not effect the coefficient of friction (going can be easy, stopping is still hard). Physics!

    1. Ed Proctor

      What about centripetal force around windy roads, Mr. Mu?

    2. Erin Burke

      And then there were 6 who didn’t heed John’s warning and showed up. 🙂

    3. Mr. Hand

      Don’t you think an example would have been appropriate to accompany the physics lesson?

      Example – Car, Braking and Required Distance to Stop
      A car with mass 2000 kg drives with speed 100 km/h on a wet road with friction coefficient 0.2.

      Note! – The friction work required to stop the car is equal to the kinetic energy of the car.

      The kinetic energy of the car is

      Ekinetic = 1/2 m v2 (3)

      where

      m = mass (kg)

      v = velocity (m/s)

      Ekinetic = 1/2 (2000 kg) ((100 km/h) (1000 m/km) / (3600 s/h))2

      = 771605 J

      The friction work (energy) to stop the car can be expressed as

      Wfriction = Ff d (4)

      where

      Ff = friction force (N)

      d = braking (stopping) distance (m)

      Since the kinetic energy of the car is converted to friction energy (work) – we have the expression

      Ekinetic = Wfriction (5)

      and (4) and (3) can be combined and modified to calculate the stopping distance of the car

      d = Wfriction / μ m g

      = (771605 J) / (0.2 (2000 kg) (9.81 m/s2))

      = 197 m

  5. Kerri

    How is Physics effecting the 9:30 tomorrow?

    1. Kerri

      Ahhhh…true….but, if 9:30 isn’t offered in mind/body …does it actually exist??

  6. ICA admin

    Ha, that’s just a mistake! Thanks for pointing it out. There is a 9:30 tomorrow! Will fix MIndbody momentarily

  7. Danielle

    Thanks for asking, Kerri!!! I was wondering about the 9:30 as well 🙂

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